12t=99t^2

Solution for 12t=99t^2 equation:

12t=99t^2

We move all terms to the left:

12t-(99t^2)=0

determiningTheFunctionDomain
-99t^2+12t=0

a = -99; b = 12; c = 0;
Δ = b2-4ac
Δ = 122-4·(-99)·0
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-12}{2*-99}=\frac{-24}{-198}
=4/33
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+12}{2*-99}=\frac{0}{-198}
=0
$